#ifndef Magnum_Math_Geometry_Distance_h #define Magnum_Math_Geometry_Distance_h /* Copyright © 2010, 2011, 2012 Vladimír Vondruš This file is part of Magnum. Magnum is free software: you can redistribute it and/or modify it under the terms of the GNU Lesser General Public License version 3 only, as published by the Free Software Foundation. Magnum is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser General Public License version 3 for more details. */ /** @file * @brief Class Magnum::Math::Geometry::Distance */ #include "Math/Vector3.h" namespace Magnum { namespace Math { namespace Geometry { /** @brief Functions for computing distances */ class Distance { public: /** * @brief %Distance of line and point * @param a First point of the line * @param b Second point of the line * @param point Point * * The distance *d* is computed from point **p** and line defined by **a** * and **b** using @ref Vector3::cross() "cross product": * @f[ * d = \frac{|(\boldsymbol p - \boldsymbol a) \times (\boldsymbol p - \boldsymbol b)|} * {|\boldsymbol b - \boldsymbol a|} * @f] * * @see linePointSquared() */ template inline static T linePoint(const Vector3& a, const Vector3& b, const Vector3& point) { return sqrt(linePointSquared(a, b, point)); } /** * @brief %Distance of line and point, squared * * More efficient than linePoint() for comparing distance with other * values, because it doesn't compute the square root. */ template static T linePointSquared(const Vector3& a, const Vector3& b, const Vector3& point) { return Vector3::cross(point - a, point - b).lengthSquared()/(b - a).lengthSquared(); } /** * @brief %Dístance of point from line segment * @param a Starting point of the line * @param b Ending point of the line * @param point Point * * Returns distance of point from line segment or from its * starting/ending point, depending on where the point lies. * * Determining whether the point lies next to line segment or outside * is done using Pythagorean theorem. If the following equation * applies, the point **p** lies outside line segment closer to **a**: * @f[ * |\boldsymbol p - \boldsymbol b|^2 > |\boldsymbol b - \boldsymbol a|^2 + |\boldsymbol p - \boldsymbol a|^2 * @f] * On the other hand, if the following equation applies, the point * lies outside line segment closer to **b**: * @f[ * |\boldsymbol p - \boldsymbol a|^2 > |\boldsymbol b - \boldsymbol a|^2 + |\boldsymbol p - \boldsymbol b|^2 * @f] * The last alternative is when the following equation applies. The * point then lies between **a** and **b** and the distance is * computed the same way as in linePoint(). * @f[ * |\boldsymbol b - \boldsymbol a|^2 > |\boldsymbol p - \boldsymbol a|^2 + |\boldsymbol p - \boldsymbol b|^2 * @f] * * @see lineSegmentPointSquared() */ template inline static T lineSegmentPoint(const Vector3& a, const Vector3& b, const Vector3& point) { return sqrt(lineSegmentPointSquared(a, b, point)); } /** * @brief %Distance of point from line segment, squared * * More efficient than lineSegmentPoint() for comparing distance with * other values, because it doesn't compute the square root. */ template static T lineSegmentPointSquared(const Vector3& a, const Vector3& b, const Vector3& point) { Vector3 pointMinusA = point - a; Vector3 pointMinusB = point - b; T pointDistanceA = pointMinusA.lengthSquared(); T pointDistanceB = pointMinusB.lengthSquared(); T bDistanceA = (b - a).lengthSquared(); /* Point is before A */ if(pointDistanceB > bDistanceA + pointDistanceA) return pointDistanceA; /* Point is after B */ if(pointDistanceA > bDistanceA + pointDistanceB) return pointDistanceB; /* Between A and B */ return Vector3::cross(pointMinusA, pointMinusB).lengthSquared()/bDistanceA; } }; }}} #endif