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#ifndef Magnum_Math_Geometry_Distance_h
#define Magnum_Math_Geometry_Distance_h
/*
This file is part of Magnum.
Copyright © 2010, 2011, 2012, 2013 Vladimír Vondruš <mosra@centrum.cz>
Permission is hereby granted, free of charge, to any person obtaining a
copy of this software and associated documentation files (the "Software"),
to deal in the Software without restriction, including without limitation
the rights to use, copy, modify, merge, publish, distribute, sublicense,
and/or sell copies of the Software, and to permit persons to whom the
Software is furnished to do so, subject to the following conditions:
The above copyright notice and this permission notice shall be included
in all copies or substantial portions of the Software.
THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL
THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING
FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER
DEALINGS IN THE SOFTWARE.
*/
/** @file
* @brief Class Magnum::Math::Geometry::Distance
*/
#include "Math/Functions.h"
#include "Math/Matrix.h"
#include "Math/Vector3.h"
namespace Magnum { namespace Math { namespace Geometry {
/** @brief Functions for computing distances */
class Distance {
public:
Distance() = delete;
/**
* @brief %Distance of line and point in 2D
* @param a First point of the line
* @param b Second point of the line
* @param point Point
*
* The distance *d* is computed from point **p** and line defined by **a**
* and **b** using @ref Matrix::determinant() "determinant": @f[
* d = \frac{|det(b - a a - point)|} {|b - a|}
* @f]
* Source: http://mathworld.wolfram.com/Point-LineDistance2-Dimensional.html
* @see linePointSquared(const Vector2&, const Vector2&, const Vector2&)
*/
template<class T> inline static T linePoint(const Vector2<T>& a, const Vector2<T>& b, const Vector2<T>& point) {
return std::abs(Matrix<2, T>(b - a, a - point).determinant())/(b - a).length();
}
/**
* @brief %Distance of line and point in 2D, squared
* @param a First point of the line
* @param b Second point of the line
* @param point Point
*
* More efficient than linePoint(const Vector2&, const Vector2&, const Vector2&)
* for comparing distance with other values, because it doesn't
* compute the square root.
*/
template<class T> inline static T linePointSquared(const Vector2<T>& a, const Vector2<T>& b, const Vector2<T>& point) {
Vector2<T> bMinusA = b - a;
return Math::pow<2>(Matrix<2, T>(bMinusA, a - point).determinant())/bMinusA.dot();
}
/**
* @brief %Distance of line and point in 3D
* @param a First point of the line
* @param b Second point of the line
* @param point Point
*
* The distance *d* is computed from point **p** and line defined by **a**
* and **b** using @ref Vector3::cross() "cross product": @f[
* d = \frac{|(\boldsymbol p - \boldsymbol a) \times (\boldsymbol p - \boldsymbol b)|}
* {|\boldsymbol b - \boldsymbol a|}
* @f]
* Source: http://mathworld.wolfram.com/Point-LineDistance3-Dimensional.html
* @see linePointSquared(const Vector3&, const Vector3&, const Vector3&)
*/
template<class T> inline static T linePoint(const Vector3<T>& a, const Vector3<T>& b, const Vector3<T>& point) {
return std::sqrt(linePointSquared(a, b, point));
}
/**
* @brief %Distance of line and point in 3D, squared
*
* More efficient than linePoint(const Vector3&, const Vector3&, const Vector3&)
* for comparing distance with other values, because it doesn't
* compute the square root.
*/
template<class T> static T linePointSquared(const Vector3<T>& a, const Vector3<T>& b, const Vector3<T>& point) {
return Vector3<T>::cross(point - a, point - b).dot()/(b - a).dot();
}
/**
* @brief %Dístance of point from line segment in 2D
* @param a Starting point of the line
* @param b Ending point of the line
* @param point Point
*
* Returns distance of point from line segment or from its
* starting/ending point, depending on where the point lies.
*
* Determining whether the point lies next to line segment or outside
* is done using Pythagorean theorem. If the following equation
* applies, the point **p** lies outside line segment closer to **a**: @f[
* |\boldsymbol p - \boldsymbol b|^2 > |\boldsymbol b - \boldsymbol a|^2 + |\boldsymbol p - \boldsymbol a|^2
* @f]
* On the other hand, if the following equation applies, the point
* lies outside line segment closer to **b**: @f[
* |\boldsymbol p - \boldsymbol a|^2 > |\boldsymbol b - \boldsymbol a|^2 + |\boldsymbol p - \boldsymbol b|^2
* @f]
* The last alternative is when the following equation applies. The
* point then lies between **a** and **b** and the distance is
* computed the same way as in linePoint(). @f[
* |\boldsymbol b - \boldsymbol a|^2 > |\boldsymbol p - \boldsymbol a|^2 + |\boldsymbol p - \boldsymbol b|^2
* @f]
*
* @see lineSegmentPointSquared()
*/
template<class T> inline static T lineSegmentPoint(const Vector2<T>& a, const Vector2<T>& b, const Vector2<T>& point) {
Vector2<T> pointMinusA = point - a;
Vector2<T> pointMinusB = point - b;
Vector2<T> bMinusA = b - a;
T pointDistanceA = pointMinusA.dot();
T pointDistanceB = pointMinusB.dot();
T bDistanceA = bMinusA.dot();
/* Point is before A */
if(pointDistanceB > bDistanceA + pointDistanceA)
return std::sqrt(pointDistanceA);
/* Point is after B */
if(pointDistanceA > bDistanceA + pointDistanceB)
return std::sqrt(pointDistanceB);
/* Between A and B */
return std::abs(Matrix<2, T>(bMinusA, -pointMinusA).determinant())/std::sqrt(bDistanceA);
}
/**
* @brief %Distance of point from line segment in 2D, squared
*
* More efficient than lineSegmentPoint() for comparing distance with
* other values, because it doesn't compute the square root.
*/
template<class T> static T lineSegmentPointSquared(const Vector2<T>& a, const Vector2<T>& b, const Vector2<T>& point) {
Vector2<T> pointMinusA = point - a;
Vector2<T> pointMinusB = point - b;
Vector2<T> bMinusA = b - a;
T pointDistanceA = pointMinusA.dot();
T pointDistanceB = pointMinusB.dot();
T bDistanceA = bMinusA.dot();
/* Point is before A */
if(pointDistanceB > bDistanceA + pointDistanceA)
return pointDistanceA;
/* Point is after B */
if(pointDistanceA > bDistanceA + pointDistanceB)
return pointDistanceB;
/* Between A and B */
return Math::pow<2>(Matrix<2, T>(bMinusA, -pointMinusA).determinant())/bDistanceA;
}
/**
* @brief %Dístance of point from line segment in 3D
* @param a Starting point of the line
* @param b Ending point of the line
* @param point Point
*
* Similar to 2D implementation
* lineSegmentPoint(const Vector2&, const Vector2&, const Vector2&).
*
* @see lineSegmentPointSquared(const Vector3&, const Vector3&, const Vector3&)
*/
template<class T> inline static T lineSegmentPoint(const Vector3<T>& a, const Vector3<T>& b, const Vector3<T>& point) {
return std::sqrt(lineSegmentPointSquared(a, b, point));
}
/**
* @brief %Distance of point from line segment in 3D, squared
*
* More efficient than lineSegmentPoint(const Vector3&, const Vector3&, const Vector3&) for comparing distance with
* other values, because it doesn't compute the square root.
*/
template<class T> static T lineSegmentPointSquared(const Vector3<T>& a, const Vector3<T>& b, const Vector3<T>& point) {
Vector3<T> pointMinusA = point - a;
Vector3<T> pointMinusB = point - b;
T pointDistanceA = pointMinusA.dot();
T pointDistanceB = pointMinusB.dot();
T bDistanceA = (b - a).dot();
/* Point is before A */
if(pointDistanceB > bDistanceA + pointDistanceA)
return pointDistanceA;
/* Point is after B */
if(pointDistanceA > bDistanceA + pointDistanceB)
return pointDistanceB;
/* Between A and B */
return Vector3<T>::cross(pointMinusA, pointMinusB).dot()/bDistanceA;
}
};
}}}
#endif